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How to make a station port go off-hook 2

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DZig

Technical User
Oct 2, 2001
6
US
Can any tell me how to make a station port go off-hook? Here's why.

I have a PC modem connected to a CO line. Through a series of zener diodes, when the modem is in use, the CO line is not available to the Partner ACS; when the modem is not in use, the CO line is available to the Partner ACS unit.

Here's the problem. When the modem is in use, the system unit does not know the CO line is not available. A station goes off hook and tries to select the line in use by the modem, but gets no dial tone. This is expected behavior. The use has to manually select the next available CO line.

What I want to accomplish is to cause an available station port to go off hook when the modem is in use. This should make the system unit select the next line (which is the modem line) marking it in use. Then when a user goes to call out, the system unit will go to the next CO line, skipping the one in use by the modem.

The underlying reason for all this is to get optimum throughput for my modem connection. Suggestions on how to avoid this would be appreciated as well. Thanks.

 
You could use one of those old "A/A1" relays, put it in line with your modem. Take the A/A1 pair and wire it with a 600 ohm resistor to a spare station port programmed to go off hook on the modem line. I think Sandman has some misc. relays in his catalog.
 
why not just hook the modem up to a port on the acs ?

program a 9 into your dial string or program that port with that line as the first in hunt


 
He will get a faster connection by connecting the modem to direct dial-tone, ahead of the ACS, than connecting to a station port. The idea is to get the ACS to busy out the CO line, so someone else doesn't go off hook where there is no dial-tone.
 
TTTommy,

Been so busy nearly forgot my manners to thank you. Ordered and got the relays from Sandman and they work like a charm. Great solution. Thanks.

DZig
 
"I think Sandman has some misc. relays in his catalog." What or who is SANDMAN? I could use this solution as well.

Thanks
Richard
 
Oldphoneguy,

Thanks for the quick and informative response.

Richard
 
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