XOR? 1

[Nebbish]

An easy one: what's the syntax for an exclusive or? I need:

if($true XOR $false)

to pass but not:

if($true XOR $true)

to pass.

Thanks,

Nick

 

[toolkit]

This works:

$a = 1; $b = 0;
if ($a xor $b) {
    print "Hello World\n";
}

Cheers, Neil

 

[Nebbish]

Heh, I guess I should have tried the obvious first, eh?

Is that the typical syntax, or is there a syntax similar to || and &&?

Thanks,

Nick

 

[toolkit]

See here for a full explanation of the operators and precedence:

http://www.perldoc.com/perl5.6/pod/perlop.html

printf "%d\n", 4 ^ 3;  ## bitwise XOR (100 ^ 011 = 111)
if(4 xor 3) {
    print "true\n";
} else {
    print "false\n";   ## 4 is true, 3 is true, hence true XOR true is false
}

There is no high precedence logical XOR operator, ie:

operation    high     low
-------------------------
'and'        &&       and
'or'         ||       or
'xor'        -none-   xor

Cheers, Neil

 

[Nebbish]

I didn't realize there was a difference between 'and' and '&&'. Thanks for the posts.

-Nick