String concatenation 1

[DerPflug]

How can I concatenate the following into a character string in the format "July 20, 2000" using the following variables?

int D,Y;
char *month = new char[10];

'month' would equal "July", 'D' would equal 20, and 'Y' would equal 2000. Do I need to convert the int's to strings as well?

Thanks.

 

[palbano]

	char* month = "July";
	int D = 20;
	int Y = 2000;

	char datebuf[50];
	sprintf( datebuf, "%s %d, %d", month, D, Y);

-pete

 

[cgafa]

#include<iostream>
#include<string>
#include<sstream>
using namespace std;

int main()
{

char *pszMonth = &quot;October&quot;;
int iDay = 21;
int iYear = 1969;
stringstream ss;

ss << iDay << &quot; &quot; << pszMonth<< &quot; &quot; << iYear;

cout<<ss.str()<<endl;

return 0;
}

cheers