Simple unix script.. 1

[galger]

I know this is simple...


Need a unix script to check if a specific process is running
every 300 second.
If it finds it, email someone....
then exit..

 

[marsd]

Not particularly simple and it's been answered many times before on this forum.

The standard way to approach it is to run a ps with options,
pipe the output through grep, filter this for the grep
process and report the OP.

A while loop and sleep fulfill your other requirement.

 

[gamerland]

procname is the name of the process you are looking to find.

cron version: (put in cron to run every 10 minutes)
#!/bin/ksh
#
PID=`ps -elf | grep procname | awk 'print { $4 }'`
if [ -z "$PID" ] ; then
print ""procname not found"
else
print "procname is running"
/maildirectory/mail -s "procname is running" youremail@yourcompany.com
fi
exit 0

Non-cron version:
#!/bin/ksh
#
PID=" " # initialization
DONE="FALSE"
while [ $DONE = "FALSE" ]
do
PID=`ps -elf | grep procname | awk 'print { $4 }'`
if [ -z "$PID" ] ; then
print "procname not found"
else
print "procname is running"
/maildirectory/mail -s "procname is running" youremail@yourcompany.com
fi
sleep 300
done

May contain minor syntax issues as I am not where I can test it. It is also possible to do this without awk if your version of grep can run silent. If so, grep will set a return code if the value is found.

 

[galger]

Thanks gamerland!!!

That worked, I changed a few things though... the grep part and the if statement. added an exit 1 to exit after emailing.

#!/bin/ksh
#
PROCESS=" " # init alias
DONE="FALSE"
while [ $DONE = "FALSE" ]
do
PROCESS=`ps -elf | grep -c ex_part1`
if [ "$PROCESS" -eq 1 ] ; then
print "proc not found" >/dev/null
else
print "proc is running" >/tmp/foo.txt
mailx -s &quot;The process has been detected!&quot; mail@mail.com </tmp/foo.txt
mailx -s &quot;The process has been detected!&quot; mail@mail.com< /tmp/foo.txt
exit 1
fi
echo &quot;sleeping......&quot;
sleep 600
done
------------------------------------------


Thanks again!!