separate averages of odd and even inputted integer numbers series

[talidyce]

I am writing a program to take a series of positive integers as input, and separately calculate and print the averages of the odd an even numbers, using a negative trip-value as end-of-data flag.
I can't figure out how to get the loop to return to the even series after jumping to the odd.
Any help would be greatly appreciated.

 

[rbobbitt]

I'm not sure I understand your problem fully. Why can't you do all the calculations on the fly?

Set up 2 variables, one for odd numbers, one for even

While user input
Get number
Figure out if it's odd or even
Add the number to the appropriate variable.

Calculate averages


Russ
bobbitts@hotmail.com

http://home.earthlink.net/~bobbitts

 

[SwapSawe]

# include <stdio.h>
# include <conio.h>

void main()
{
int Num = 1,no_of_odd = 0,no_of_even = 0;
int OddsTotal,EvensTotal;
float avg_even,avg_odd;
printf(&quot;THIS PROGRAM CACULATES ODDS AVG AND EVENS AVG DIFFERENTLY&quot;
while(Num > 0)
{
printf(&quot;Enter a negetive number to Exit :&quot;
scanf(&quot;%d&quot;,&Num);
if(num <= 0) break;
if(num%2==0)
{
EvensTotal+=num;
no_of_even++;
}
if(num%2!=0)
{
OddsTotal+=num;
no_of_odd++;
}
}
avg_even = EvensTotal/no_of_even;
avg_odd = OddsTotal/no_of_odd;
printf(&quot;Average of Even Nos. Entered : %f&quot;,avg_even);
printf(&quot;Average of Odd Nos. Entered : %f&quot;,avg_odd);
}

So this is the code arq.


I hope this was not an assignment.
Happy Learning,
SwapSawe.

 

[rbobbitt]

># include <stdio.h>
># include <conio.h>

Don't need this header

>
>void main()

main() returns int:

int main()

>{
>int Num = 1,no_of_odd = 0,no_of_even = 0;
>int OddsTotal,EvensTotal;

You have to initialize these to 0:

int OddsTotal=0,EvensTotal=0;

>float avg_even,avg_odd;
>printf(&quot;THIS PROGRAM CACULATES ODDS AVG AND EVENS AVG >DIFFERENTLY&quot;

fflush(stdout);

Since output is usually line-buffered, this ensures the user will see the prompt before they can enter input.

>while(Num > 0)
> {
> printf(&quot;Enter a negetive number to Exit :&quot;

fflush(stdout);

> scanf(&quot;%d&quot;,&Num);
> if(num <= 0) break;

0 isn't a legal value?

> if(num%2==0)
> {
> EvensTotal+=num;
> no_of_even++;
> }
> if(num%2!=0)
> {
> OddsTotal+=num;
> no_of_odd++;
> }
> }
>avg_even = EvensTotal/no_of_even;
>avg_odd = OddsTotal/no_of_odd;
>printf(&quot;Average of Even Nos. Entered : %f&quot;,avg_even);
>printf(&quot;Average of Odd Nos. Entered : %f&quot;,avg_odd);

printf(&quot;Average of Even Nos. Entered : %f\n&quot;,avg_even);
printf(&quot;Average of Odd Nos. Entered : %f\n&quot;,avg_odd);

>}
>
>So this is the code arq.
>
>
>I hope this was not an assignment.

It probably was, that's why I didn't post any code. I always make it a point not to do so unless the OP demonstrates that they've put some of their own effort into the problem.

Russ
bobbitts@hotmail.com

http://home.earthlink.net/~bobbitts

 

[talidyce]

Thank you very much for the quick and informative answers rbobbitt and SwapSawe.
This fixed my problem. It was indeed part of an assignment and I had been trying to work out this particular one for 3 days and in frustration decided to call for help. We were going to review the questions with the teacher and finalise them before handing in the assignment, so I did not feel I was cheating by seeking third party help.
Thanks again for helping