Jerry is "correct", but the answer is somewhat limited.
The datediff function returns the number of
Intervals (the "d"

between the two date arguments.
Consider the following:
DaysOld = DateDiff("d", FirstDate, SecondDate)
? FirstDate, SecondDate, DaysOld
3/21/01 11:59:59 PM 3/23/01 5:47:44 PM 2
3/21/01 12:00:01 AM 3/23/01 5:46:43 PM 2
Although the FirstDate varys by 23H 59M and 58Sec, both differences are
2 days.
So, you need to carefully Know (and DEFINE) the term "two days".
MichaelRed
redmsp@erols.com
There is never time to do it right but there is always time to do it over