RegEx wizard help needed

[webfuture]

I have this long string
/usr/lib/vmware/bin/vmware-vmx -C /vmware/vm-machines/vm-cs-xp-84/xp_pro_english_base.vmx -@ ""

And need to print only this part "vm-cs-xp-84" inside it.

What regex could do that. I know it's doable but not with my limited knowledge. What I would do and want to avoid is multiple splits.

Thanks in advance.

Simon

 

[duncdude]

one way - fine if your directory path doesn't change...

[b]#!/usr/bin/perl[/b]

$_ = '/usr/lib/vmware/bin/vmware-vmx -C /vmware/vm-machines/vm-cs-xp-84/xp_pro_english_base.vmx -@ ""';

@components = split(/\//);

print $components[8];

Kind Regards
Duncan

 

[rharsh]

Here's a regex that should work for you:

my $str = '/usr/lib/vmware/bin/vmware-vmx -C /vmware/vm-machines/vm-cs-xp-84/xp_pro_english_base.vmx -@ ""';
$str =~ m!vm-machines/([^/]+)! && print "$1\n";

Using split would really work just fine too, you don't need more than one:

my @fields = split '/', $str;
print "$fields[8]\n";

 

[rharsh]

Yeah, what Duncan said! (Looks like I was a bit slow.)

 

[duncdude]

;-)

... a bit neater with rharsh's literal '/' though


Kind Regards
Duncan

 

[webfuture]

Thanks to all... That's so easy....

I do perl 1 week per year and regex 1 hour per year... Everytime I go back to this I get lost.

I have used the split, it will be easier to debug in the long run, since I am no expert on Regex

Thanks again

Simon