Random 12digit password generator

Karl Blessing · Mar 8, 2000

I need something that'll create a quick alphanumeric(a->z, A->Z, 1->0) 12 digit character array 
something i can just throw in a char something[13]; 
Karl <a href=mailto:kb244@bellsouth.net>kb244@bellsouth.net</a> <a href=

http://kb244.8m.com>

</a>

Karl Blessing · Mar 9, 2000

Ok i looked into it, got something made, tho microsoft MSDN was no help at all, and i do remeber there used to be a random command where you just stick in the ranges, but M$ had no info on this instead i came up with this lil example 
 
#include <iostream.h> 
#include <stdlib.h> 
#include <stdio.h> 
#include <time.h> 
 
void main( void ) 
{ 
int i,j; char tmp[13]; 
i=j=0; 
srand( (unsigned)time( NULL ) ); 
for( i = 0; i <= 12;i++ ) 
{ 
 
while((j<48) ¦¦ ((j>57)&&(j<65)) ¦¦ ((j>90)&&(j<97)) ¦¦ (j>122)) 
{ 
j = rand(); 
} 
tmp = j; 
cout<<j<<' '; 
j=0; 
} 
tmp[13]='\0'; 
cout<<'\n'<<tmp; 
} 
/* 
48->57 numbers 
65->90 capital letters 
97->122 lowercase letters 
*/ Karl <a href=mailto:kb244@bellsouth.net>kb244@bellsouth.net</a> <a href=

http://kb244.8m.com>

</a>

ssingh · Mar 28, 2000

Hi Kb244,    When I ran your code . It was not working properly. But the problem is interesting , so I dared to try it out. I 've pasted the code below. Please have a look over it Also I made a change in for loop because if you go for 0 to 12 , it is actually 13 byte long password . But you want to generate for 12 only. Although you've explicitly pushing null at 13th position. Thanx Siddhartha Singh <A HREF="mailto:ssingh@aztecsoft.com">ssingh@aztecsoft.com</A> #include <iostream.h> #include <stdlib.h> #include <stdio.h> #include <time.h> void main( void ) { int i,j; char temp[13]; srand( (unsigned)time( NULL ) ); /* For twelve no. it should start from 0 to 11. */ for( i = 0; i < 12;i++ ) { switch(j=rand() % 3) {  /* Random for small,capital and numbers */ case 0: /* For small letters    */ j = 48 + rand() % 10; temp = (char) j; break; case 1: /* For capital letters  */ j = 65 + rand() % 26; temp = (char) j; break; case 2: /* For Numbers          */ j = 97 + rand() % 26; temp = (char) j; break; } /* End Switch */ } /* End For */ temp='\0'; cout<<'\n'<<"The password:" <<temp << '\n'; return ; } /*                           48->57 numbers                           65->90 capital letters                           97->122 lowercase letters                           */

DigitalPython · Apr 4, 2000

i ran the program and it worked... i don't understand HOW to actually implement this generator in a larger or FOR WHAT reason?

ssingh · Apr 5, 2000

The reason might be anything . Either for an assignment, or for your own interest , etc... This is the way to learn more and more siddhartha Singh <A HREF="mailto:ssingh@aztecsoft.com">ssingh@aztecsoft.com</A>

Guest_imported · Apr 11, 2000

I've done something like this, and here was my approach (this is just pseudocode): char lpPasswordChars [32] = "abcdefghijkl"; void GenPassword (char * buffer) {    char lpPassword[12];     for (i = 0; i < 12; i++)    {     //create a random number     int foo = rand()*1000;      //use it to index into the array     lpPassword = lpPasswordChars[foo%11];    } } The idea is to use a random index to an array.  Now you can control exactly the character set that will be drawn from without worrying about ASCII values or ranges.

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Random 12digit password generator

Karl Blessing

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Karl Blessing

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ssingh

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DigitalPython

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ssingh

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