"complex" find command

[illmatic]

Hi all,

I have to run a complex "find command" but do not get the exactly information I want to.

In fact I want to find all "scripts" located on the systems which contain a specific "path".

I set it up in this way "find / -exec grep 'pattern' {} \;"
but the result shows only the lines where the "pattern" occurs
and not the name of the file/script which does not help me at all.

Maybe there is an additionally parameter in the syntax needed which I just don´t know? Otherwise I think I will have to write a script for this issue.

Thank you so far

Alex

 

[hoinz]

Hi,

the reason for this behaviour: grep will not tell you the file name, if there is just 1 file; it will always be just 1 if the file name comes from a find command.

There are two possible workarounds, depending on what exactly you need:

1) if you need the file name, but not the actual result of grep command:
find / -exec grep -l 'pattern' {} \;"

2) if you need the result of grep as well:
find / -exec grep 'pattern' {} \; -exec ls {} \;
You will get first the lines in the file, then the file name.
Changing order of the two execs will not work.

regards

 

[illmatic]

Yes,

it seems to be working fine!
Thank you so far.

By the way I used the grep -l option.

Regards

Alex