Query URL Question

[brinker]

Hi Everyone,

I know how to get the content for basic HTML pages using Java. However, when I try to get the content for something like "

http://inventory.overture.com/d/searchinventory/suggestion/?term=telephone.com",

Java responds that I am including an illegal character (ie '?') in the URL. I know that ColdFusion can handle this sort of thing. Can Java?

If Java can handle this sort of URL, could somebody tell me how to get around the problem that I am having.

thanks

 

[palbano]

you need

suggestion?term=telephone.com

or

suggestion/mypage.jsp?term=telephone.com

or ... etc.

-pete

 

[brinker]

No, that doesn't seem to be working. If I put the '?' anywhere in the URL, I get a Java error.

The URL must be the same, at least the host must see it as the same to get the page required. When I try placing the '?' somewhere else using a browser, I get a different page.

 

[harmmeijer]

Here is something I found to post data:
public void send(String data) {
try {
System.out.println("Data: " + data);

//URL encode the data to the x-

http://www-form-urlencoded

MIME format
String urlEncodedData = URLEncoder.encode(data);
System.out.println("URL Encoded Data: " + urlEncodedData);

//Instance the URL (protocol, host, port)
String protocol = getCodeBase().getProtocol();
int port = getCodeBase().getPort();
String host = getCodeBase().getHost();
URL url = new URL(protocol, host, port, "/servlet/ProxyServlet"
System.out.println("Destination URL: " + url.toString());

//Open the connection
urlConnection = url.openConnection();

//Turn off the caching feature
urlConnection.setUseCaches(false);

//Set the URL to POST instead of GET
urlConnection.setDoOutput(true);

//Set necessary properties
urlConnection.setRequestProperty("content-type",
"application/x-

http://www-form-urlencoded");

urlConnection.setRequestProperty("content-length",
String.valueOf(urlEncodedData.length()));

//Get the output stream and send the data
PrintStream outStream =
new PrintStream(urlConnection.getOutputStream());
outStream.println(urlEncodedData);
outStream.close();
System.out.println("Data sent successfully"
}
catch(Exception e) {
System.out.println("URL Connection error: " + e.toString());
}
}


Complete code is here:

http://www.ddj.com/ftp/1998/1998_06/jqa698.txt

When you want to use get to send data it is a lot simpler I think you pass the querystrng in the URL.

http://java.sun.com/j2se/1.4.1/docs/api/java/net/URL.html

Take a look at the set method of the URL (since 1.3)

 

[brinker]

I think that I've figured it out this morning. I had to make a string first, then put it into the URL. This works for queries.

 

[palbano]

>> I had to make a string first, then put it into the URL

could you explain or show that? How else could you put it in the URL if it's not a string?

-pete

 

[brinker]

From what I can tell, if I tried something like new URL("

http://inventory.overture.com/d/searchinventory/suggestion/?term=hello"),

I get an error.

However, if I tried :
new t = new String("

http://inventory.overture.com/d/searchinventory/suggestion/?term=hello")

g = new URL(t);

This is fine.

I may be wrong, but from what I can tell this seems to work. Weird.

 

[palbano]

I just executed the following line of code without error:

java.net.URL url = 
	new java.net.URL("[URL unfurl="true"]http://inventory.overture.com/d/searchinventory/suggestion/?term=hello");[/URL]

I believe your problem was somewhere else.

-pete