problem with include path

[alfalf]

Hello.

I have this setting in my PHP.ini:
include_path = "c:\php\includes\phpmailer"

but when i require file class.phpmailer.php (wich is placed in c:\php\includes\phpmailer\) like:
require("class.phpmailer.php"

I get this message:
Fatal error: Failed opening required 'class.phpmailer.php' (include_path='c:\php\includes\phpmailer') in C:\Apache2\htdocs\test_mail.php on line 10

I have W2K, PHP4 as binary, on Apache2.

Thanks for any suggestions.

 

[sleipnir214]

Does Apache's user have permission to read the file?

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[alfalf]

Yes.

 

[DRJ478]

When in doubt always write out the entire path for the include. It just makes it clearer.

 

[csniffer]

".;c:\php\mylib" isn't there suppose to be a dot then a semicolon first on windoz here is mine but to be honest i dont use it
include_path = ".;C:\Program Files\Apache Group\libr"

To err is human, to completely mess up takes a computer.

 

[alfalf]

yes yes, it is , there's no doubt about .; syntax. It's all ok. I must tell, that all this was on Apache2.

But, since I need SSL also, only yesterday I installed Apache 1.3.27 mod_ssl 2.8.11 open SSL 0.9.6g and one older PHP version 4.2.2 (i had 4.2.3) and for now testing both (http and https) servers with my pages.

So for now, I can't tell more how include/require/require_once behaves (I haven't came to that part), and also I have some new aspects to think about. grrr.

Never the less, I'll post what hapend, and want to say thanks to all here.


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