php image adress

[801119]

Greetings all...

I have absolutly no idea what I'm looking for, then only thing I know is the "adress" part!

Lets say an image is located at: [URL unfurl="true"]http://www.internet.com/images/img.jpg[/URL]
and I want it to look like this when it opens:
[URL unfurl="true"]http://www.internet.com?img=img.jpg[/URL]

or <img src=&quot;[URL unfurl="true"]http://www.internet.com?img=img.jpg&quot;>[/URL]

if you understand what I'm after?!

My codes look like something a kid wrote
I have absolutely no idea what I am talking about
Somehow I still manage to make it work

 

[sleipnir214]

I don't get you.

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[801119]

Well, perhaps what I want is for my php page to write the image directly through the code. I know I saw it somwehere, but not sure where. But can't really find it again o)

My codes look like something a kid wrote
I have absolutely no idea what I am talking about
Somehow I still manage to make it work

 

[sleipnir214]

What exactly does "write the image directly through code" mean?

Want the best answers? Ask the best questions:

http://www.catb.org/~esr/faqs/smart-questions.html

TANSTAAFL!!

 

[Vragabond]

Hmmm, are you looking for something like this?

$img = "/images/";
$img .= $_GET['img'];

echo &quot;<img src=\&quot;$img\&quot; />&quot;;

Nothing else comes to mind. Hope it helps.

 

[801119]

No, lets say that the images are outside of server-root and there fore not accessable for the webserver, so I need php to access them for me.

lets say server root is
C:/apache/

http://wwwroot/

and the images are locaed out side
C:/images/

Now the server can't acces them, right? So I need php to access them for me, so when a certain image is needed that I do not want the webserver to access, the php code will do it for me?

Any clearer, or am I as usual talking gibberish ;D

My codes look like something a kid wrote
I have absolutely no idea what I am talking about
Somehow I still manage to make it work

 

[sleipnir214]

You're clear.

The HTML will look something like:

<IMG src=&quot;/foo.php?imgname=bar.jpg&quot;>

And your script will stream out the image from somewhere outside your document root.

The &quot;gotcha&quot; is that you'll need two scripts: one to output the actual HTML of the page, the other to do the image streaming. Well, you could do it with one, but I recommend using two.

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http://www.catb.org/~esr/faqs/smart-questions.html

TANSTAAFL!!