Passing in an element from an Array of Pointers

[azntekkan]

Hi, I'm trying to use an array to hold some information from a file. Here is my code.


byte * buffer[30];

for(int j=0;j<30;i++)
{
buffer[j]=(byte *)malloc(518400);
}

//then i open a file-this part has no problems

ReadFile(videoYUV,buffer[1],518400,&bytesread,&gOverLapped);


The read in part fails. But when I use a regular pointer (i.e byte * buffer=(byte *) malloc(518400) )it works. I was wandering if i'm passing in the pointer wrong or something. Please help me out. Thanks in advance.

 

[RbgoWeb]

Don't really understand what you're doing.
Anyway, maybe this helps

BYTE* FileToBuffer(char* szFileName, DWORD* lpdwSize)
{
HANDLE hFile;
DWORD dwSize, dw_nobr;
BYTE* bytes;

//Obtain a handle to the file
hFile = CreateFile(
szFileName,
GENERIC_READ,
0,
NULL,OPEN_EXISTING,
FILE_ATTRIBUTE_NORMAL,
NULL);

//Get size of the file
dwSize = GetFileSize(hFile, NULL);

//Allocate space for file data
bytes = (BYTE *)malloc(dwSize);

//Read file data into buffer
ReadFile(hFile, bytes, dwSize, &dw_nobr, NULL);

//Done with the handle
CloseHandle(hFile);

//Set the size
lpdwSize = dwSize;

//ofcourse...
return bytes;
}

I left out error handling for clarity.

 

[AMosmann]

do not know, but try

ReadFile(videoYUV,*buffer[1],518400,&bytesread,&gOverLapped);
or
ReadFile(videoYUV,*(buffer[1]),518400,&bytesread,&gOverLapped);
or
ReadFile(videoYUV,(*buffer)[1],518400,&bytesread,&gOverLapped);



Greetings Andreas

 

[azntekkan]

Thnx, its working now