Parsing the output of ps command

[new2unix]

Hi,

I am writing a script to issue a Unix ps command and with some grep to give a sample output such as this:

application_name -m some_value -p some_value -C some_value -d 0 -c 0

The value I am really after is the some_value after "-p". What would be the best way to extract the value right after the "-p" parameter assuming the "-p" may appear any where (but just once) after the application_name?


Thanks

Mike

 

[flawless69]

$input_line =~ /-p\s(.*)\s-C/;
$some_value = $1;[\code]

and then $1 will be your "some value" --Derek

[i]"Fear not the storm for this is where we grow strong."[/i]

 

[new2unix]

Derek,

Thanks! I am off to a good start. But just in case, should I skip the part on checking for "-C" at the end? Since the "-p" may appear any where in the output line, it may show up after "-C".

Mike

 

[flawless69]

Ah yes....
Then I suggest a slight modification:

$input_line =~ /-p\s([\s^-])/;

I think this will make sure to stop before the next dash or space. The way it was before, it would grab the rest of the line without the -C. --Derek

"Fear not the storm for this is where we grow strong."

 

[flawless69]

oops, dang it move the ^ to before the \s --Derek

"Fear not the storm for this is where we grow strong."

 

[new2unix]

Hi Derek,

This is what I ended up using based on your suggestion:

$port =~ /-p.(\d+)/;
$port = $1;

I was able to get the value specifically associated with "-p". Not sure if there is an another way to accomplish the same on one single statement. But, this would do.

Thanks

Mike