Parsing a String

[jtanner]

Hello,

In a Bourne shell script I have a variable length string that is enclosed in parenthesis.

Examples

echo "$CONN1" (2msec)
echo "$CONN2" (10msec)
echo "$CONN3" (100msec)

How can I get ride of the parenthesis?

Thanks,

JT

 

[aigles]

You can use tr :

echo "$CONN1" | tr -d '()'

Jean-Pierre.

 

[sbrews]

I'm assuming that (2msec) is what is contained in variable CONN1. Based on that assumption, this will remove the parens:

CONN1=`echo $CONN1| tr -d '()'`
echo $CONN1
2msec

Add a little color to your PUTTY terminal: faq52-6627

 

[sbrews]

It appears that aigles is faster on the keyboard than me.

Add a little color to your PUTTY terminal: faq52-6627

 

[PHV]

The good old legacy Bourne shell...
what about this ?

expr "$CONN1" : '(\(.*\))'

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[p5wizard]

With sed:

CONN1=$(echo "${CONN1}"|sed 's/[()]//g')

or

CONN1=`echo "${CONN1}"|sed 's/[()]//g'`

HTH,

p5wizard

 

[jtanner]

Guys,

All your suggestions were simple and brilliant.

Thanks,

JT

 

[p5wizard]

Here's a less "simple" solution ;-):

CONN1=$(echo "${CONN1}"|fold -w1|grep -v '('|grep -v ')'|tr -d '\n')

HTH,

p5wizard