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Overloading Operators...
- Thread starter Phred
- Start date
Cagliostro
Programmer
Look one sample:
#include<iostream>
using namespace std;
class x
{
public:
int xx;
};
ostream& operator<<(ostream& c,x& a)
{
return c<<a.xx;
}
int main()
{
x a;
a.xx=0;
cout<<a<<endl;
return 0;
} John Fill
ivfmd@mail.md
#include<iostream>
using namespace std;
class x
{
public:
int xx;
};
ostream& operator<<(ostream& c,x& a)
{
return c<<a.xx;
}
int main()
{
x a;
a.xx=0;
cout<<a<<endl;
return 0;
} John Fill
ivfmd@mail.md
Zyrenthian
Programmer
Doing it for fstream works fine. I have always put the overloading into the .h files or into the structs i create and just inline them. Here is an example.
friend ofstream& operator << (ofstream& o,
<user defined type> my_type)
{
...// output my_type how you want (output to "o"
return o;
}
the same goes for all other streams.
Matt
friend ofstream& operator << (ofstream& o,
<user defined type> my_type)
{
...// output my_type how you want (output to "o"
return o;
}
the same goes for all other streams.
Matt
Akay.. so I will try again with another explanation (as nothing work 
)
I want to creat a fonction/class which accept to use the operator<< with a string like this:
TOutput l_output;
_output.open("test.fichier", ofstream:
ut | ofstream::app);
_output<< "Output\n";
_output.close();
and in the "test.fichier" file I want to have:
SysLog Output
So the problem is:
How to make an operator like this one
friend ofstream& operator << (ofstream& o,
<user defined type> my_type)
{
...// output my_type how you want (output to "o"
return o;
}
returning the string o = "Syslog "+mystring;
*Sob* One day and I still can't find how to do
)I want to creat a fonction/class which accept to use the operator<< with a string like this:
TOutput l_output;
_output.open("test.fichier", ofstream:
ut | ofstream::app);_output<< "Output\n";
_output.close();
and in the "test.fichier" file I want to have:
SysLog Output
So the problem is:
How to make an operator like this one
friend ofstream& operator << (ofstream& o,
<user defined type> my_type)
{
...// output my_type how you want (output to "o"
return o;
}
returning the string o = "Syslog "+mystring;
*Sob* One day and I still can't find how to do
Zyrenthian
Programmer
If I understand this correctly, i think all you need to do is when you declare your ofstream, open it how you would like (i.e. ios::app | ios:ut)
example
class foo{
public:
...
friend ofstream& operator << (ofstream& O,
foo my_foo)
{
O<<my_foo.value1<<endl<<my_foo.value2;
return O;
}
private:
int value1,value2;
};
int main()
{
ofstream output("output.txt",ios::app|ios:ut);
foo my_foo(1,2);// sets value1 to 1 and value2 to 2
...
output<<my_foo;
return 0;
}
// expected output is:
// 1
// 2
Matt
ut)example
class foo{
public:
...
friend ofstream& operator << (ofstream& O,
foo my_foo)
{
O<<my_foo.value1<<endl<<my_foo.value2;
return O;
}
private:
int value1,value2;
};
int main()
{
ofstream output("output.txt",ios::app|ios:
ut);foo my_foo(1,2);// sets value1 to 1 and value2 to 2
...
output<<my_foo;
return 0;
}
// expected output is:
// 1
// 2
Matt
SOLVED:
void TFichier:perator<<(char* p_string)
{
ofstream l_out("File.txt", ios:ut | ios::app);
_donnee = p_chaine; // _donnee is a class value
l_out << "SysLog " << _donnee;
l_sortie.close();
}
Sorry.. it was simple but I miss the point
lol
void TFichier:
perator<<(char* p_string){
ofstream l_out("File.txt", ios:
ut | ios::app);_donnee = p_chaine; // _donnee is a class value
l_out << "SysLog " << _donnee;
l_sortie.close();
}
Sorry.. it was simple but I miss the point
lol
*- Status