linear search/string sorting

beauafric · Sep 22, 1999

am supposed to Write a program that creates an 
Employee database (held in memory) by prompting the 
user for the information. 
Each entry in the database is composed of an 
employee 
name (a string) and an employee identification 
number(a number between 100 and 200). The database holds 
five 
entries. After the database has been created the 
program prints it out in name order. 
 
The problem i can't figure out is the ordering of the employee name. I currently get a bunch of errors. Am just one week old in java so am pretty much clueless... 
if someone could look at it and give me some guidance 
or some pointer it will be greatly appreciated. 
 
cheers 
 
 
import java.io.*; 
import java.util.Locale; 
import java.text.Collator; 
import java.text.CollationKey; 
 
 
class EmployeeException extends Exception 
{ 
public EmployeeException(String msg) 
{ 
super(msg); 
} 
} 
 
class Worker 
{ 
public String name; 
public int number; 
 
public Worker() 
{ 
BufferedReader keyboard = new BufferedReader(new InputStreamReader(System.in)); 
try { 
System.out.print("Enter an Employee name:"); 
name = keyboard.readLine(); 
} 
catch (IOException iox) { 
System.out.println("I/O error"); 
} 
 
try { 
System.out.print("Enter an Employee identification number:"); 
number =Integer.parseInt(keyboard.readLine()); 
} 
catch (IOException iox) { 
System.out.println("I/O error"); 
} 
catch (NumberFormatException numx) { 
System.out.println("Num error"); 
} 
 
if (number < 100 ¦¦ number > 200) { 
System.out.println("Identification number must be a number between 100 and 200"); 
} 
} 
 
public void print() 
{ 
System.out.print(name); 
System.out.print(" "); 
System.out.print(number); 
} 
} 
 
class Employees 
{ 
private final static int MaxSize=5; 
private Worker[] staff; 
 
public Employees() 
{ 
staff=new Worker[MaxSize]; 
 
for (int i=0; i<MaxSize; i++) { 
Worker newStaff=new Worker(); 
staff=newStaff; 
} 
} 
 
public void sort(String[] input) { 
Collator c=Collator.getInstance(Locale.CANADA_FRENCH); 
CollationKey[] ckeys=new CollationKey[input.length]; 
for (int i=0;i<input.length;i++) { 
ckeys=c.getCollationKey(input); 
} 
 
CollationKey tempKey; 
for (int i=1;i<ckeys.length;i++) { 
for (int j=0;j<ckeys.length-i;j++) { 
if (ckeys[j].compareTo(ckeys[j+1]) > 0) { 
tempKey=ckeys[j]; 
ckeys[j]=ckeys[j+1]; 
ckeys[j+1]=tempKey; 
} 
} 
} 
for (int i=0;i<input.length;i++) { 
input=ckeys.getSourceString(); 
} 
} 
 
public void print() 
{ 
for (int i=0; i< MaxSize; i++) { 
staff.print(); 
System.out.println(); 
} 
} 
} 
 
public class Lab2 
{ 
 
public static void main(String args[]) 
{ 
Employees myStaff=new Employees(); 
System.out.println(); 
System.out.println("The Employee Database"); 
myStaff.print(); 
} 
}

Otto · Sep 23, 1999

Hi! 
 
I do not understand your program, only correct it (syntactically, 
not functionality). Here is the corrected Lab2.java: 
 
 
import java.io.*; 
import java.util.Locale; 
import java.text.Collator; 
import java.text.CollationKey; 
 
 
class EmployeeException extends Exception 
{ 
public EmployeeException(String msg) 
{ 
super(msg); 
} 
} 
 
class Worker 
{ 
public String name; 
public int number; 
 
public Worker() 
{ 
BufferedReader keyboard = new BufferedReader(new InputStreamReader(System.in)); 
try { 
System.out.print("Enter an Employee name:"); 
name = keyboard.readLine(); 
} 
catch (IOException iox) { 
System.out.println("I/O error"); 
} 
 
try { 
System.out.print("Enter an Employee identification number:"); 
number =Integer.parseInt(keyboard.readLine()); 
} 
catch (IOException iox) { 
System.out.println("I/O error"); 
} 
catch (NumberFormatException numx) { 
System.out.println("Num error"); 
} 
 
if ((number < 100) ¦¦(number > 200)) { 
System.out.println("Identification number must be a number between 100 and 200"); 
} 
} 
 
public void print() 
{ 
System.out.print(name); 
System.out.print(" "); 
System.out.print(number); 
} 
} 
 
class Employees 
{ 
private final static int MaxSize=5; 
private Worker[] staff; 
 
public Employees() 
{ 
staff=new Worker[MaxSize]; 
 
for (int i=0; i<MaxSize; i++) { 
staff=new Worker(); 
} 
} 
 
public void sort(String[] input) { 
Collator c=Collator.getInstance(Locale.CANADA_FRENCH); 
CollationKey[] ckeys=new CollationKey[input.length]; 
for (int i=0; i<input.length; i++) { 
ckeys=c.getCollationKey(input); 
} 
 
CollationKey tempKey; 
for (int i=1; i<ckeys.length; i++) { 
for (int j=0; j<ckeys.length; j++) { 
if (ckeys[j].compareTo(ckeys[j+1]) > 0) { 
tempKey=ckeys[j]; 
ckeys[j]=ckeys[j+1]; 
ckeys[j+1]=tempKey; 
} 
} 
} 
for (int i=0; i<input.length; i++) { 
input=ckeys.getSourceString(); 
} 
} 
 
public void print() 
{ 
for (int i=0; i< MaxSize; i++) { 
staff.print(); 
System.out.println(); 
} 
} 
} 
 
public class Lab2 
{ 
 
public static void main(String args[]) 
{ 
Employees myStaff=new Employees(); 
System.out.println(); 
System.out.println("The Employee Database"); 
myStaff.print(); 
} 
} 
 
 
 
Good luck. Bye, Otto.

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linear search/string sorting

beauafric

Programmer

Otto

Programmer

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