Lazy XSLT question

[toolkit]

Suffering a mental block. Anyone have a quick template to turn "some.string.with.delims.foo" to "foo"? I don't think the substring-after function will do the trick unless I recurse it?

 

[toolkit]

Sussed it:

<xsl:template name="getLastToken">
    <xsl:param name="tokens"/>
    <xsl:variable name="cropped" select="substring-after($tokens,'.')"/>
    <xsl:choose>
        <xsl:when test="contains($cropped,'.')">
            <xsl:call-template name="getLastToken">
                <xsl:with-param name="tokens" select="$cropped"/>
            </xsl:call-template>
        </xsl:when>
        <xsl:otherwise>
            <xsl:value-of select="$cropped"/>
        </xsl:otherwise>
    </xsl:choose>
</xsl:template>

But is there an easier way for this?
Cheers, Neil

 

[toolkit]

<xsl:template name="getLastToken">
    <xsl:param name="tokens"/>
    <xsl:variable name="cropped" select="substring-after($tokens,'.')"/>
    <xsl:choose>
        <xsl:when test="not(contains($tokens,'.'))">
            <xsl:value-of select="$tokens"/>
        </xsl:when>
        <xsl:when test="not(contains($cropped,'.'))">
            <xsl:value-of select="$cropped"/>
        </xsl:when>
        <xsl:otherwise>
            <xsl:call-template name="getLastToken">
                <xsl:with-param name="tokens" select="$cropped"/>
            </xsl:call-template>
        </xsl:otherwise>
    </xsl:choose>
</xsl:template>

 

[jel]