Nov 28, 2006 #1 stephm923 Programmer Joined Nov 28, 2006 Messages 9 Location US I need to create a formula that will give me the last day of the current month (ex. 2006-11-30)
Nov 28, 2006 #2 synapsevampire Programmer Joined Mar 23, 2002 Messages 20,180 Location US Try: dateserial(year(currentdate),month(currentdate)+1,1)-1 -k Upvote 0 Downvote
Nov 28, 2006 #3 bdreed35 Programmer Joined Mar 2, 2003 Messages 1,549 Location US Here is one way to do it: dateadd("m",1,minimum(monthtodate))-1 ~Brian Upvote 0 Downvote
Nov 28, 2006 #4 lbass Technical User Joined Feb 9, 2002 Messages 32,818 Location US Try: dateserial(year(currentdate),month(currentdate)+1,1)-1 -LB Upvote 0 Downvote
Nov 28, 2006 Thread starter #5 stephm923 Programmer Joined Nov 28, 2006 Messages 9 Location US Worked like a charm. Thanks!! Upvote 0 Downvote