KILL and Removing a registry entry and file

[ch0s3n]

Okey first of all i am Really really new to Visual Basic (6) i'm makin a program that get's rid of a virus that infected people's computer when they went to buddypicture.net (now shut down but there is still alot of people infected) i got the rest all pretty but i'm havin some probs

1. i have this to try to kill the process

Private Sub Command1_Click()
 Kill "C:\WINDOWS\av.exe"
End Sub

and i get Run-Time error '53' file not found. but it DOES exist

2. i'm not so sure about the DeleteSetting command. i'm trying to get Private Sub Command5_Click() to remove the following setting from the registry.

the key

HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows\CurrentVersion\Run

and removing the string

AntiVirus REG-SZ c:\WINDOWS\av.exe

from that key

3. Sub Delete() is that the right thing to use to delete c:\windows\av.exe ? if it is could i get a hint on the Syntax?

Please help

Thanx alot

VB Newbie!

 

[dex1123]

Hello, ch0s3n. I am not in Visual Basic programming but probably some hints can be of help to you. I don't know if 'kill' or 'Delete' is the sub that you use in VB to delete files. Since this is a WinAPI forum I can tell you that you can use the

DeleteFile

api call which probably 'kill' or 'delete' reference to in order to function. As for registry key removal you can use

RegDeleteValue

call. You can check their params in Win32 SDK. You should have it installed with your VB I guess. Otherwise, I am not so sure if VB has escape characters like C. If it does, you probably should write your 'kill' line like this:

Kill "C:\\WINDOWS\\av.exe"

in order to escape the backslash. This is how it is done in C for example. I don't say it will work that way but just it might. A VB programmer should be of greater help. Why don't you make a post to a Visual Basic programming forum. Try this one forum222 Tek-tips have more of these VB forums. You should check on those ones too. That's all from me. Hope it helps a bit.

best regards,
Ivan


A well-defined problem is half solved.