Is there a function to read the contents of a directory?

[tristero]

Is there a function to read the contents of a directory into a string or array? thanks.

 

[sleipnir214]

Not a single function, no.

But PHP has a family of directory functions. To see example code on listing a directory, look at the online manual page for readdir():

http://www.php.net/manual/en/function.readdir.php

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[jtaal]

Try this:

<?
$dircontent = `ls -m /images/etc`; // backtick
$files = $explode(&quot;, &quot;, $dircontent);
?>

this gives you an array of files in /images/etc. I'f you're familiar with ls you can provide other options. Of course this only works on UNIX servers, not on windows or other incompatible ones...

 

[tristero]

i've tried everything from readdir to scandir (turns out my server only supports php4 and this is a php5 function)...

i keep getting "openbase_dir restriction is in effect"

does this mean that i can't use these functions?

 

[sleipnir214]

What that means is that your PHP installaction only allows PHP's filesystem and directory functions to operate within the document root of a web site.

If this is your own machine, tweak php.ini.

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[tristero]

So i can't use directory functions on subdirectories?

this is not my machine, is there no work around?

 

[sleipnir214]

You can, but the directories on which you operate must be under the directory specified by the open_basedir command.

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[tristero]

how do i find out which directory is specified by the open_basedir?

i believe i am trying to read directories that are within these boudaries...

i can't even get opendir() to work...

<?
if ($handle = opendir('/images/')) {


   closedir($handle); 
}
?>

 

[sleipnir214]

If you invoke phpinfo(), you should be able to see what PHP's settings are.

If the "images" directory is a subdirectory of where your script resides, you want to issue:
opendir('images')
not
opendir('/images')

PHP's filesystem and directory functions operate on filesystem paths, not document root paths. So the first invocation above is trying to open the directory "/images", where the second is trying to open "/path/to/your/script/images".

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[tristero]

Ahhhahahahahaa

that was it!

/

thank you!!!

it always seems to come down to a / or a ;