Ints and std::string

[SmileeTiger]

Can anyone think of a more readable way to convert an int to a std::string then what I have below:

std::string FilePath;
std::stringstream ss;
std::string FileNum;

for(int i=0 ; i < 5; i++)
{
ss << i;
ss >> FileNum;

FilePath = "/blah/blah/FileName" + FileNum + ".txt";
cout << "File to open:" << FilePath << endl;
}

 

[cpjust]

I modified Microsoft's itoa() function to use std::string instead of char* and made it a template...
That way it can convert any base instead of just oct, hex & dec.

 

[chipperMDW]

Encapsulate your solution in a function template:

  template< typename To, typename from >
To lexical_cast( From f )
{
    To t;
    stringstream stream;
    stream << f;
    stream >> t;
    return t;
}


FilePath = "/blah/file" + lexical_cast<string>(num) + ".txt";

Add error checking.

It works for converting anything to anything, assuming the <<-input representation of one can convert to the >>-output representation of another.


See

http://www.boost.org

for the "real" lexical_cast, which has much better error cheching than this one.

 

[jstreich]

Since it is just from 0 to five....

for(int i=0 ; i < 5; i++)
{
  char num = (char)(i + (int)'0');
  FilePath = "/blah/blah/FileName" + num + ".txt";
  cout << "File to open:" << FilePath << endl;
}

should work, fairly clear what your doing and why, and is less lines... The stream is better code in some respects, worse in others. writing a itoa or a general function as others has mentioned would be the way to go if you had to do it a million times.