I need help passing an array between functions without it being global 1

[soas]

Hey guys, I am a novice programmer, with no formal experience. I think this is common knowlege amoung programmers with formal training, but how do i pass an array between two functions?
I know I cant do it like this
Void blah(int x[10][10])
I am barely familiar with pointers, but not enough to know if thats what i need to use here, to pass the array between two functions without making it global. The thing is I wouldnt even ask if i had a clue what to look for to learn it myself, but i just dont know what to look for to find the answer. I would be very greatful if someone could help me with possible ways to do this. If you need me to explain better what I am trying to accomplish, I will try my best.
If it is pointers that I need to use, I should add that I only know the idea of pointers, not how to use them, so if someone could show an example or where to learn about them I would be equally happy with that. I did look up pointers, but apparently its a much broader subject than I anticipated. I will be greatful for any help at all, thanks!

 

[Kenrae]

You don't need to define size. You should write

void blah(int x[][])

or

void blah(int *x)

.
When you call the procedure, variable size should be reserved. A sample code could be:

int main(){
int x[10][10];

blah(x);
}

A rule about pointers you'll always have to take into account is that you must always have its size reserved before using it. For example if you wrote this:

int main(){
int *x;

blah(x);
}

it would compile, but it wouldn't be correct. It would usually crash.

Think on pointers as an arrow pointing at something be it an int, char, string or whatever you like.

 

[soas]

woohoo, thank you! that part just confused me
I would have always considered x the variable to be totally different than x the array, the part that always threw me off was the blah(x), i would do blah(x[][])
Thanks Alot!

 

[smaniraja]

Use the following decleartion for passing Two Dimensional arrays ( its array of arrays ) to a function.

#include <iostream.h>
void show(int (*)[3]);
int main()
{
int a[3][3] ={10, 20, 30, 40, 50, 60, 70, 80, 90};
show(a);
return 0;
}

void show(int (*arg)[3])
{
int i, j;
for(i = 0; i < 3; i++)
for(j = 0; j < 3; j++)
cout << endl << arg[j];
}
Here the (*arg)[3] is a pointer to a 3 element array. While using like this you should know the row(number of arrays) size within the function otherwise pass it to the function.

Maniraja S