How to take a string with only numbers and convert it to an int...

[danielnogo]

Is there anyway to take a string with only numbers and covert it to an integer? I know you can do it vice versa.

 

[bcemick]

I usually just use aoti:

int nNumber = 0;
CString string;
atoi(&string);

 

[timmay3141]

Yep just use atoi, there's also an atof to convert to a double if you need it.

 

[danielnogo]

Okay, so if I have a string that has just numbers inside of it, and I want to put it inside an int, i'd do this?:

int TheNumbers= 0;
atoi(m_sNums);

Then, how do I load it into the integer variable?

 

[snuv]

int theNumbers = atoi(m_sNums);

"If it could have gone wrong earlier and it didn't, it ultimately would have been beneficial for it to have." : Murphy's Ultimate Corollary

 

[xwb]

If you are using CStrings, then it really needs a LPCTSTR operator i.e.

CString msrope;
msrope = "1234";
int x = atoi((LPCTSTR) msrope);

Similarly, if you are using STL strings

string stlrope;
stlrope = "1234";
int x = atoi (stlrope.c_str());

 

[PerFnurt]

>If you are using CStrings, then it really needs a LPCTSTR operator i.e.

Which since it is a type operator will implicitly be invoked when needed. That's why a call like

CString msrope;
msrope = "1234";
int x = atoi(msrope);

works. (in non-unicode anyway)

>Similarly, if you are using STL strings

Which do not have such operators, hence you must call the c_str() method to get it as a const char*

/Per

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