i tried to connect this:
x=inet1.openurl(url)
but if the "url" doesn't exist or doesn't work, how can i get a unable to connect status, then ill display an error message?
Thanks.
One of the difficulties of error handling in general in VB6 is that there is more than one way to do it. In particular with controls, it's often a matter of looking through some properties that the control exposes.
Googling on "openurl method error handling" yields a good deal of information on this.
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