How do I code an automatec job execution

[Tison]

I would like the following job to run via root cron ;
LOGF="/usr/local/erp/oraerp/ss.log"
su - newuser -c "date
for fil in `ls /mydir/*.sh`
do
sh $fil >> $LOGF
done
date"

The job must do the following steps ;
1 Show date
2. for each file in the mydir
executre the file
3. Show date

I get this error ;
ksh: syntax error at line 2 : `/mydir/st2.sh' unexpected

 

[predamarcel]

the error is in file
`/mydir/st2.sh'

 

[daFranze]

execute the script the following way

sh -x myscript

what is the output?

Regards
-- Franz
Sorry I'm not a native spaeker, I'm from Munich, Germany - "Home of the Whopper", oh no, "Home of the Oktoberfest" ;-)

 

[Tison]

The problem is not /mydir/st.sh becuase I can run it fine by itself.
The problem is in the loop somewhere where it seems to read the first entry only. Note that the scripts is trying to do a loop within an su session.

 

[KenCunningham]

Why are you doing it that way. Why not put the script in a wrapper and call the wrapper from your su? Or am I missing something (well, it is Friday afternoon!).

 

[sbix]

Try to substitute the " character with a ' wich is equivalent.
The problem is in the interpretation of $ symbols

 

[jj3301]

I agree with KenCunningham - I think the problem is that &quot;su - <name> -c&quot; objects to getting a multi-line command. Hopefully, if you put the script into a file that is then called by su it will all work.

I'm also slightly worried by the error message coming from from ksh when you call the /mydir/*.sh scripts as &quot;sh $fil&quot;.

Good luck.

 

[sbix]

Nope, there aren't any problem in the multi line but, if it sounds better tison can put all the command in a variable and then execute:
su - user -c &quot;$variable&quot;

 

[sbix]

I confirm my previous post, just tried what suggested and works.
Substitute &quot; with '