help with IFF and MOD functions!

[NeoTurtle]

Hi everyone. I've been up all night trying to figure something out. I could get it working if I could just understand what this means in plain English:

<TR BGCOLOR=&quot;#IIF(((CurrentRow MOD 2) IS 0),DE('FFFFFF'),DE('EEEECC'))#&quot;>

I tried looking all my help references which turned out to be helpLESS. MOD returns the remainder of integer1 in MOD(integer1, integer2)??
Does that mean something like:
3 divided by 2 is 1.5
so the value returned is .5????
Now my book says that a Similar CF Expression would be:
integer1 MOD
If my expample of 3 divided by 2 is 1.5 is correct, then how does it know what to divide by in something like:
3 MOD

Or could it be that I've been up too long???? Geez . . . most people are waking up at this time!

Thanks in advance,
-NeoTurtle
[sig][/sig]

 

[manny]

This is a simple way of alternating the background color of each row in a table. The mod function when used with the divisor 2 always returns a 1 or a 0. Using it this way changes the background color of every other row in the table. [sig][/sig]