format partition question

[ponetguy2]

does this look okay? I dumber today that yesterday.

Part Tag Flag Cylinders Size Blocks
0 unassigned wm 0 0 (0/0/0) 0
1 unassigned wu 0 0 (0/0/0) 0
2 backup wu 0 - 65532 135.99GB (65533/0/0) 285199616
3 unassigned wm 0 0 (0/0/0) 0
4 unassigned wm 0 - 11 25.50MB (12/0/0) 52224
5 unassigned wm 0 0 (0/0/0) 0
6 unassigned wm 12 - 65066 135.00GB (65055/0/0) 283119360
7 unassigned wm 0 0 (0/0/0) 0

 

[bfitzmai]

You have 25.50 MB labled in Partition 4 and 135 GB labled in Partition 6. The cylinder numbers don't add up to the cylinder number in Partition 2. You final cylinder should be 65532. Partition 4 looks okay since you should have a little over 2 Meg per cylinder. It's partition 6 I don't like. I would start from scratch... If this is the way you want to partition you disk, use the Modify option under Format-->Partition. Use the "All Free Hog" option (option 1). After a couple questions asking if you want to start from a default table to if you are ready, enter 6 for the Free Hog Partition (This is the default selection)... Enter 0 for partition 0, 1, 3... Enter 25.50 mb for partition 4... Enter 0 for partition 5 and 7. The new table will print out and if you like it, enter the lable and save the partition table.

 

[ponetguy2]

thank you, bfitzmai. i appreciate your help.

 

[ponetguy2]

is this better?

Part Tag Flag Cylinders Size Blocks
0 unassigned wm 0 0 (0/0/0) 0
1 unassigned wu 0 0 (0/0/0) 0
2 backup wu 0 - 34980 68.32GB (34981/0/0) 143282176
3 unassigned wm 0 0 (0/0/0) 0
4 unassigned wm 0 - 11 24.00MB (12/0/0) 49152
5 unassigned wm 0 0 (0/0/0) 0
6 unassigned wm 12 - 34827 68.00GB (34816/0/0) 142606336
7 unassigned wm 0 0 (0/0/0) 0

 

[kHz]

I would partition it by moving your slice 4 to slice 0 and your slice 6 to slice 1, then put the remainder (cylinders 34828-34980) in slice 6. Then when you glance at the partition table you will know exactly how much is free. But why not just add the remainder to slice 4? Slice 6 is slower than slice 0, too.

 

[kHz]

I should clarify that 6 wouldn't be slower than 0 if the cylinders both contained the same (e.g., 0-28000) but if you have multiple slices, remember the lower cylinders are faster. That is why root and swap are at the beginning.

 

[ponetguy2]

thank you kHz. I did'nt think about that. I'll definetly consider your suggestion.

 

[bfitzmai]

Ponetguy,
Here is a partition table from one of my Sunblades...

PARTITION MENU:
0 - change `0' partition
1 - change `1' partition
2 - change `2' partition
3 - change `3' partition
4 - change `4' partition
5 - change `5' partition
6 - change `6' partition
7 - change `7' partition
select - select a predefined table
modify - modify a predefined partition table
name - name the current table
print - display the current table
label - write partition map and label to the disk
!<cmd> - execute <cmd>, then return
quit
partition> p
Current partition table (original):
Total disk cylinders available: 19156 + 2 (reserved cylinders)

Part Tag Flag Cylinders Size Blocks
0 root wm 0 - 501 1000.08MB (502/0/0) 2048160
1 swap wu 502 - 760 515.98MB (259/0/0) 1056720
2 backup wm 0 - 19155 37.27GB (19156/0/0) 78156480
3 usr wm 761 - 2266 2.93GB (1506/0/0) 6144480
4 var wm 2267 - 3270 1.95GB (1004/0/0) 4096320
5 unassigned wm 3271 - 5780 4.88GB (2510/0/0) 10240800
6 home wm 5781 - 19155 26.02GB (13375/0/0) 54570000
7 unassigned wm 0 0 (0/0/0) 0

Notice the end cylinder value for Partition 6 is equal to the value of Partition 2 (Full Disk). Also notice that if you add up all the size values for all the partitions, it is very close to the size value in partition 2. This is what I was talking about when I said I didn't like the values you had for your partition 6.