eval question

[tankim]

I have an html form that has several textboxes (<input type=&quot;text&quot. What I want to do is to allow users to enter numbers and number equations like +, -, /, and * into the textbox, and display the result on the textbox. For example, user will enter &quot;200 / 4&quot; and the form will display &quot;50&quot;.

When onblur event happens, I do an eval on the content of the textbox, forcing the calculation of the contents of the textbox. I then replace the contents of the textbox with the result from eval. It works fine if I enter &quot;200 / 4&quot; or &quot;200&quot;. &quot;200 / 4&quot; gives me &quot;50&quot;, &quot;200&quot; gives me &quot;200&quot;. However, when I enter &quot;0200&quot;, I am getting &quot;128&quot;. It seems like the problem happens if the number entered starts with &quot;0&quot;.

Could someone englighten me on this?

Thanks in advance.

 

[mwolf00]

It assumes the number is a hexadecimal when it starts with a &quot;0&quot; and you eval or parseInt it...

Programming today is a race between software engineers striving to build better and bigger idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning. - Rick Cook (No, I'm not Rick)

 

[tankim]

Thanks.

Do you have a suggestion on how to get around this?

 

[mwolf00]

Check that last post - numbers starting with a zero are seen as octals(base-8) values - so long as the next digit (after the inital 0) is between 0 and 7.

If you were just using parseInt, you could add a radix arguement(10) to let it know that you are working with decimal numbers - that isn't possible with the eval() function...

The only solution I see is to pull the string apart... yuck... You may want to see if the first number is a zero and alert the user...

Programming today is a race between software engineers striving to build better and bigger idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning. - Rick Cook (No, I'm not Rick)

 

[tankim]

Thanks.

I think I will try to use regular expression to strip off leading zeroes. See how much success I have on this approach