easily count instances in a hash array 1

[1DMF]

Hello,

I was wondering if there was an easy way to count how many indexes in an array of hashes contain a key equal to a specific value.

a for loop and count mechanism seems clunky, so thought you experts could come up with a one liner ;-)

"In complete darkness we are all the same, only our knowledge and wisdom separates us, don't let your eyes deceive you.

 

[brigmar]

I'm hardly an expert, but here's my stab:

my %hashthing = ( abc => 1, def =>2, ghi =>3, jkl => 1 );
[b]my $count = grep { $_ eq "1" } values %hashthing ;[/b]
print $count;

Internally, it does all the same thing as a loop mechanism, just that the source code for the count fits on one line.

 

[MillerH]

Array of hashes. Sure thing.

my $count = scalar grep {exists $_->{$key} && $_->{$key} eq $value} @array;

- Miller

 

[brigmar]

Oops. I misread the question. Ignore me.

 

[1DMF]

Spot on! Nice Job MillerH ;-)

"In complete darkness we are all the same, only our knowledge and wisdom separates us, don't let your eyes deceive you.