displaying middle part of strings.

[AndyDoyle]

Just a quickie,

I have some various length strings, which are all '\n' terminated.
However I need to display them broken up into different parts.

eg if one is 20 chars and I need to break up into 4 chars then 12 chars then 4 chars.

cvhh cjhbsdhcjugh bhsy

Thankyou.
Sorry its not more technical.

 

[marsd]

You just need a strncpy wrapper probably.

char *wrapIt(char *target, int offset, int len) {
char *place, *new;

   /*make sure the options are sane*/
   if (len <= (strlen(target) - offset)) {
       /*move to beginning of selection*/
       place = target + offset;
       /*allocate memory for new string*/
       new = malloc(len + 1 * sizeof(char));

            if (new) {
            /* if we've got mem cut string */
               strncpy(new,place,len);
            /* terminate the string*/
               new[len + 1] = '\0';
               return new;
            }  
    }
/* we can check for a NULL return now and know
that an error occurred, more specific errors
could be diagnosed for invalid args or memalloc
failure*/
return NULL;
}

Usage:
char *pstr;
pstr = wrapIt("This is a bogus string",5,3);
printf("%s\n", pstr);