Covert string to an array

[OOzy]

Hello

How can I convert this string to an array

a=1,3,4

such as

b[0]=1
b[1]=3
b[2]=4

 

[rpet]

You can use strtok() to extract the numbers from the string.


char p[] = "1, 3, -6, 0, 129";
int a[5], index = 0;

char * token = strtok(p, ","

while(token) {
a[index++] = atoi(token);
token = strtok(0, ","
}

 

[Zyrenthian]

you could also do this a different way as well

int getNextInt(char* array)
{
int return_value = atoi(array);
array = strstr(array,",&quot+1;
return return_value;
}

int main()
{
...
char* array = a;


while(array)
{
b[index++]=getNextInt(array);
}

}

I suggest this because i have had problems with strtok in the past. strstr has always treated me well

Matt

 

[Cagliostro]

#inlcude<strstream>
using namespace std;
int main()
{
strstream x;
char* z;
int y=0;
x<<y;
z=x.str();
x>>y;
return 0;
} John Fill

ivfmd@mail.md