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How do I pass a char** in IDL

How do I pass a char** in IDL

How do I pass a char** in IDL

I'm new to IDL and have not had much luck finding a good tutorial online.

If I have a simple C client program:-

int main(int argc, char **argv) {

How do I declare the interface in IDL?

I've tried the following but it gives the following error:
test.idl: 4:syntax error after string
test.idl: 4:expected one of: <, identifier
test.idl: 4:instead of *

module mymodule {
  interface myinterface {
    long myoperation(in long a, in string **b);

RE: How do I pass a char** in IDL

passing of char** through IDL does not make sence, because it could be used only inside the same thread or process, so if you would like to pass an array of strings, you should pass sequence of strings:

typedef sequence<string> sq_strings;
long myoperation(in long a, in sq_strings b);

Ion Filipski

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