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slurping files quickly

slurping files quickly

slurping files quickly


Is there a one line way to slurp a file into an array?

Instead of
open(FILE, "file") ¦¦ warn "couldn't open file";
@array = <FILE>;

I would like to
@array = <"file">;

I know, it's just a couple of lines, but Larry Wall himself says that lazyness is a virtue. :)

I saw someone do this:
@array = `/bin/cat file`;

but I want to stay in perl.

- Kai.

RE: slurping files quickly

For quick and dirty, it seems like 'cat' is a very reasonable way to do this.... unless you are interested in controlling the child process .... or .....you want to make the code portable to other OS's which might not have 'cat'....like a M$ windows PC.... ( which is available from Cygwin).

RE: slurping files quickly

Don't think you'd be able to do this, the reason being that you have to open the file before you can read it. No way around it (that I'm aware of). One way of simulating what you want would be to create a subroutine along the lines of:

sub slurp {
my $Filename = $_[0];
my @File_Array;
open(MYFILE, "<$Filename");
@File_Array = <MYFILE>;

Then call it as:

@File_Stuff = slurp("/path/to/my/file");

RE: slurping files quickly

Yeah, that's kind of what I thought. Be handy if it were built in, but I guess I'll make a module similar to what you wrote. Thanks.

RE: slurping files quickly

The line...

@file = <ARGV>;

will actually slurp the contents of a filename passed in as a parameter without requiring that you open the file.  So, if you call the above line 'slurp.pl' and start the script as such...

perl slurp.pl test.txt

the entire contents of test.txt will be slurped into @file, even though you didn't explicity open it.

Strange, but true.

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