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Run-Time error '2109':

Run-Time error '2109':

Run-Time error '2109':

(OP)
Help... On my form i have a button that does several things...
1). Saves the record
2). Prints the current record
3). Advances to the next new (blank) form (record)
4). Places the cursor at the field named ETR as the starting point for the next new record.

Often times but not every time I get an error message that
says:
Run-Time error '2109'
There is no field named 'ETR' in the current record.

I then have an option to END or DEBUG,
When I click DEBUG the code that is highlighted is:
DoCmd.GoToControl "ETR"

I DO clearly have a field named ETR in both the table and form.

My entire code for this button is as follows:

Private Sub Command23_Click()


    DoCmd.DoMenuItem acFormBar, acRecordsMenu, acSaveRecord, , acMenuVer70
    DoCmd.PrintOut acSelection
    DoCmd.GoToRecord , , acNewRec
    DoCmd.GoToControl "ETR"

Exit_Command23_Click:
    Exit Sub

   
End Sub

Is something wron or missing???
I am using Access 97 on Windows 98

Thanks again,
csegal@arrowair.com

RE: Run-Time error '2109':

Try this....

Instead of-

DoCmd.DoMenuItem acFormBar, acRecordsMenu, acSaveRecord, , acMenuVer70
DoCmd.PrintOut acSelection
DoCmd.GoToRecord , , acNewRec
DoCmd.GoToControl "ETR"

Use-
   
DoCmd.Save acForm, "YourFormName"
DoCmd.PrintOut acSelection
DoCmd.GoToRecord , , acNewRec
Me.ETR.setfocus

Hope this helps.

RE: Run-Time error '2109':

you can also just set the tab order of the form so that ETR is the first field, then it will always go there and you dont have to write any code for it.

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