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extract month to order, from calculated field

extract month to order, from calculated field

extract month to order, from calculated field

Hi guys
I have a query which returns a calculated field of type date
i would like to order my records by the month of that field
something like:

  select distinct pe.commencedate, sn.skillid, s.name sname, sn.timeperiodid, tp.weeks, p.name pname, p.companyid, (pe.commencedate + (weeks * 7)) as RequiredBy
from personemployment pe
join person p on p.personid = pe.personid
join skillneeded sn on sn.employmentid = pe.employmentid
left join timeperiod tp on tp.timeperiodid = sn.timeperiodid
join skill s on s.skillid = sn.skillid
where p.companyid = 1
and ((pe.commencedate + (weeks * 7)) >= '3/12/03' and (pe.commencedate + (weeks * 7)) <= '3/12/04')
and sn.skillid not in
(select skillid from skillattempt where (personid = p.PersonID and skillid = sn.skillid
and result = 'P' and (validto is null or validto > '3/12/03')))
                order by extract(month from 8)

only firebird1.0 doesnt like extract there.  is there a way i can do this?
Software Developer / Web Master
(025) 213-1065

RE: extract month to order, from calculated field


Put the 'extract(...' into the start of the select statement (to simplify the 'order') and use the field number only in the 'order'.

select distinct extract(month from (pe.commencedate+(weeks*7))), ...
order by 1


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