FindFirst Method

&lt;very puzzled look indeed&gt; Could you post an example of what you mean?<br>
<br>
Mike

Tell me if this is what you mean:<br>
<br>
Ex. 1. Recordset.FindFirst "LastName='" & NameVar & "'"<br>
Namevar must be a string variable that does not include quotation marks.<br>
<br>
Or if you're not getting results, you may have dealt with numbers or dates which should not br enclosed in single quotes. For dates enclose searchstring in #. like "Date &gt; #" & DateVar & "#".<br>
Or you need to simplify your code to make it look like Ex.1 above. <br>
Or maybe we can look at your sample code bec. I have to agree with Mike. <br>
<br>

Thanks for looking at this. I realize how confuse I sound and as a beginner, teaching myself VB 5.0, I am confused and appreciate your help.<br>
<br>
I understand Ex 1 from rameses would work fine as long as NameVar does not include quotation marks. My NameVar may or may not contain quotation marks. <br>
<br>
Below is my wrong and corrected (hopefully) code where Double_Quote() is a function I wrote which searches for a single quote and pads any single quote found with a single quote. (ie If NameVar = "Bob's" Double_Quote returns "Bob''s")<br>
<br>
Wrong Ex2:<br>
rs.FindFirst ("LastName='" & Double_Quote(NameVar) & "'")<br>
<br>
Corrected Ex2:<br>
rs.FindFirst "LastName='" & Double_Quote(NameVar) & "'"<br>
<br>
<br>
<br>