Python Armstrong Number print
Python Armstrong Number print
(OP)
I need to print all armstrong numbers ranging from 1 to 10000. My issue is that when my programme runs and hits 150, it does nothing.
as opposed to
As a result, it does not display 153 (an Armstrong number), because the total is 152. I'm not sure whether other numbers are performing the same thing. Yet, as shown here, I checked up to 200 and there is no problem with any other numbers except those in the 150-160 area.
Is this a compiler bug? Is it necessary to reinstall my compiler? I'm currently utilising codeblocks.
CODE --> python
(1^3) + ((6^3)-2) + (0^3)
as opposed to
CODE --> python
(1^3) + (6^3) + (0^3)
As a result, it does not display 153 (an Armstrong number), because the total is 152. I'm not sure whether other numbers are performing the same thing. Yet, as shown here, I checked up to 200 and there is no problem with any other numbers except those in the 150-160 area.
Is this a compiler bug? Is it necessary to reinstall my compiler? I'm currently utilising codeblocks.
CODE --> python
#include <iostream>
#include <math.h>
using namespace std;
int main()
{
for(int i = 0;i <= 1000;++i)
{
int r = i;
int dig = 0;
while(r != 0)
{
dig++;
r /= 10;
}
int n = i, sum = 0;
while(n != 0)
{
int d = n % 10;
sum += pow(d, dig);
n /= 10;
}
if(sum == i)
cout << i << ' ';
}
cout << "\n\n\n";
return 0;
} 
Talk To Other Members
RE: Python Armstrong Number print
The power operator in python is not ^ but **:
>>> 1**3 + 5**3 + 3**3
153
The code on the link you provided works well
https://www.scaler.com/topics/armstrong-number-in-...
I tried it
CODE
# https://www.scaler.com/topics/armstrong-number-in-python/ def check_3_digit_armstrong(number): temp = number add_sum = 0 while temp != 0: k = temp % 10 add_sum += k*k*k temp = temp//10 if add_sum == number: print('The number %3d is a three-digit Armstrong Number' % number) def check_n_digit_armstrong(number): digits = len(str(number)) temp = number add_sum = 0 while temp != 0: # get the last digit in the number k = temp % 10 # find k^digits add_sum += k**digits # floor division # which update number with second last digit as last digit temp = temp//10 if add_sum == number: print('The number %6d is %d-digit Armstrong Number' % (number, digits)) if __name__ == "__main__": print("3-digit Armstrong numbers") for number in range(100, 1000): check_3_digit_armstrong(number) print() print("n-digit Armstrong numbers") for number in range(100, 1000001): check_n_digit_armstrong(number)and got this output:
CODE