Related to Average 1

Bhashi · Oct 14, 2022

HI All,

I Have a table like below,

Code:

[b]EmpID  Name  Salary  Department[/b]

I want to find the employees in each department who earn more than average salary in that department. How to write this query in SQL. Please help. I'm new to SQL Programming.

I tried the below query but it did not give the correct output. [ponder]

Code:

select * from Employee E1 where Salary > (select avg(salary) from Employee E2  where E2.Department = E1.Department )

Thank you.

Andrzejek · Oct 14, 2022

There will be a couple of steps to do. First you need to get the 'average salary in ~~that~~ [every] department.'
[tt][blue]
Select Department, AVG(Salary) As AVG_Salary
From Employee Group By Department[/blue][/tt]

And the second step would be to incorpoprate step one into:

[pre]Select E.EmpID, E.Name, E.Salary, A.AVG_Salary, E.Department
From Employee E,
([blue]Select Department, AVG(Salary) As AVG_Salary
From Employee Group By Department[/blue]) A
Where E.Department = A.Department
And E.Salary > A.AVG_Salary[/pre]

---- Andy

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Related to Average 1

Bhashi

Programmer

Andrzejek

Programmer

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