I have a series of lab label/factor pairs in a list of tuples. I need to work through the factorPotency list retaining the label/factor pairs with the highest factor value in the event of duplicate label names e.g. 'chain'.
The algorithm is roughly this: leave you to do the coding
Create a dictionary
Iterate through factorPotency
If the value exists in the dictionary, take the greater value
if it does not exist, add it to the dictionary
I got the required result via the below routine. I am intrigued by the suggested dictionary approach. If someone could attempt the dictionary method I would be grateful to further my learning.
@xwb thanks for your response.
CODE
factorPotency = [('chain', 100), ('compound', 100), ('sequence', 95), ('crystcont', 80), ('sequence', 75), ('chain', 67)]
MAX = len(factorPotency)
uniqueLabel = []
effectiveFactorPotency = []
print(factorPotency)
for i in range(MAX):
factorPotencyList = list(factorPotency[i])
label = factorPotencyList[0]
factor = factorPotencyList[1]
if label not in uniqueLabel:
uniqueLabel.append(label)
effectiveFactorPotency.append( (label,factor) )
print(effectiveFactorPotency)
$ python labpot.py
[('chain', 100), ('compound', 100), ('sequence', 95), ('crystcont', 80), ('sequence', 75), ('chain', 67)]
[('chain', 100), ('compound', 100), ('sequence', 95), ('crystcont', 80)]
Thank you @mikrom. You are quite right. I should have provided more background and context to this task. This task is the final part of a larger piece of work.
The 'factorPotency' list has already been pre-sorted by a routine by the second data-pair item (the numeric). The final outstanding issue that required addressing was the removal of 'lower' numeric data-pairs for a given label.
I would certainly be interested in an alternate approach to this task, perhaps as suggested with a dictionary, to advance my understanding. Thank you for responding.
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RE: List of tuples issue
Create a dictionary
Iterate through factorPotency
If the value exists in the dictionary, take the greater value
if it does not exist, add it to the dictionary
Convert dictionary back into a list
RE: List of tuples issue
I got the required result via the below routine. I am intrigued by the suggested dictionary approach. If someone could attempt the dictionary method I would be grateful to further my learning.
@xwb thanks for your response.
CODE
factorPotency = [('chain', 100), ('compound', 100), ('sequence', 95), ('crystcont', 80), ('sequence', 75), ('chain', 67)] MAX = len(factorPotency) uniqueLabel = [] effectiveFactorPotency = [] print(factorPotency) for i in range(MAX): factorPotencyList = list(factorPotency[i]) label = factorPotencyList[0] factor = factorPotencyList[1] if label not in uniqueLabel: uniqueLabel.append(label) effectiveFactorPotency.append( (label,factor) ) print(effectiveFactorPotency) $ python labpot.py [('chain', 100), ('compound', 100), ('sequence', 95), ('crystcont', 80), ('sequence', 75), ('chain', 67)] [('chain', 100), ('compound', 100), ('sequence', 95), ('crystcont', 80)]RE: List of tuples issue
You wrote, that you need pairs with the highest factor value, but if you change your input list to
CODE
factorPotency = [('chain', 67), ('compound', 100), ('sequence', 75), ('crystcont', 80), ('sequence', 95), ('chain', 100)]CODE
[('chain', 67), ('compound', 100), ('sequence', 75), ('crystcont', 80)]RE: List of tuples issue
The 'factorPotency' list has already been pre-sorted by a routine by the second data-pair item (the numeric). The final outstanding issue that required addressing was the removal of 'lower' numeric data-pairs for a given label.
I would certainly be interested in an alternate approach to this task, perhaps as suggested with a dictionary, to advance my understanding. Thank you for responding.