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sed substitution within bash script with mixed quotes

sed substitution within bash script with mixed quotes

sed substitution within bash script with mixed quotes

I am trying to update some legacy php code via some sed substitutions running in a bash script.
Some items seem to work fine; others not so much. The issue appears to be when the substitution strings contain single or double quotes.
I have tried a variety of means of escaping the quotes; but, have had no success.
Here is an example line from my bash script:

/usr/bin/sed -i 's/(session_is_registered('ADMIN')/$_SESSION["group_code"]=='ADMIN'/g' /home/impact/php_repair_temp/*.php 

I wish to replace: session_is_registered('ADMIN')
With: $_SESSION["group_code"]=='ADMIN'

Other substitutions without quotes in the string are working fine...

-Allen M.

RE: sed substitution within bash script with mixed quotes


CODE --> command line

/usr/bin/sed -i 's/(session_is_registered('"'"'ADMIN'"'"')/$_SESSION["group_code"]=='"'"'ADMIN'"'"'/g' /home/impact/php_repair_temp/*.php 

Alternatively you can just move the Sed code to a Sed script file to avoid shell quoting problems :

CODE --> command line

/usr/bin/sed -i -f transform-my-code.sed /home/impact/php_repair_temp/*.php 

CODE --> transform-my-code.sed



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