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Why can't I display the index in this task array

Why can't I display the index in this task array

Why can't I display the index in this task array

Hi all, smile
I'm a bit stuck here in terms of how to display the index number for debugging...
I want to display the value of each i ( index ) so I can see what the index value is at any point in the loop.
It seems to work for the first value each time, but then gives 0 for all others..
Please help, this will give me better understanding of how the WaitAll works...please see code below.
Thanks bigsmile

CODE --> c#

private static void TaskWaitAny()
            // Task [array] <of return type integer> or direct as Task<of return type integer>[that is an array of tasks]
            Task<int>[] tasks = new Task<int>[3];
            tasks[0] = Task.Run(() => { Thread.Sleep(2000); return 1; });
            tasks[1] = Task.Run(() => { Thread.Sleep(2000); return 2; });
            tasks[2] = Task.Run(() => { Thread.Sleep(2000); return 3; });
            while (tasks.Length > 0)
                int i = Task.WaitAny(tasks);  // WaitAny(): Returns: The index of the completed task in the tasks array argument.
                int y = i;
                Task<int> completedTask = tasks[i];
                Console.WriteLine("completedTask.Result: {0} same as tasks[i].Result: {1} and y (current i val) is: {2} ", completedTask.Result, tasks[i].Result, y);

                // code below creates a list of the tasks, then removes an entry at i
                // then overwrites the tasks array with the new array with one less item
                //.'. list gets smaller each time and no inifinite loop
                List<Task<int>> temp = tasks.ToList();
                tasks = temp.ToArray();


Thank you,

Kind regards


RE: Why can't I display the index in this task array

It waits 2 seconds for the first task to finish. By that time, the others have also finished so they exit. Try


tasks[0] = Task.Run(() => { Thread.Sleep(2000); return 1; });
            tasks[1] = Task.Run(() => { Thread.Sleep(4000); return 2; });
            tasks[2] = Task.Run(() => { Thread.Sleep(6000); return 3; }); 

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