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.PerformClick() on open Form

.PerformClick() on open Form

.PerformClick() on open Form

I have a form (A) that has a hyperlink to an edit form (B).
I would like to see the changes reflected on form A, after I have edited the records on form B. I have this code in from B,


This works, but opens another instance of form A that reflects the changes made.
I guess A.show() opens another instance but
I would like to see the changes in the original form.

RE: .PerformClick() on open Form

No, the .Show() method does not open a new instance. If another instance of Form A is opening, you are probably creating a new instance of Form A when Form B opens, rather than passing a reference to the existing Form A.

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