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awk match substitution using regexp "^" and a variable name

awk match substitution using regexp "^" and a variable name

awk match substitution using regexp "^" and a variable name


I want to do a gawk statement were the following is matched but it does not work:

temp="(partners ?x1 ?x2";
if ( temp ~ /^\(/variable/ ?/ ){
print hello;

The following works, so the problem is getting the variable value of "partners" inside the regexp.

if ( temp ~ /^\(partners ?/ )
I tried using match function instead, but keep getting errors, e.g:
if (match(temp,"^\("variable" ?") ){
I get the error:
gawk: ../../../scripts/Hikin-3Dto2D-PDDL.awk:147: fatal: :, [., or [=: /^(partners ?/

To summarize, can I do a search in gawk that uses both regexp "^" for beginning of string and also a variable as part of the string to match???


RE: awk match substitution using regexp "^" and a variable name


You have to specify the regular expression as string to be able to concatenate it with a variable :

CODE --> Awk

if ( temp ~ "/^\\(" variable " ?" ){ 
Just watch out the escaping.


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