print first line unconditionally

w5000 · Sep 19, 2016

hello,

I'd like to get whole 1st line (header line, makred in blue) printf in each iteration in below for loop.

What I get now is:

Code:

# cat inputtest
===> hostA: transfer 16/09/2016,00:00:01 - 16/09/2016,23:59:59          5        42.64
===> hostB: transfer 16/09/2016,00:00:01 - 16/09/2016,23:59:59          3        65.24
===> hostA: transfer 17/09/2016,00:00:01 - 17/09/2016,23:59:59          7        22.54
===> hostB: transfer 17/09/2016,00:00:01 - 17/09/2016,23:59:59          7        36.34
# for a in hostA hostB;do echo "---==== $a ====---";{ echo "[COLOR=#3465A4]date files size[/color]";grep $a: inputtest|tr -s ' '; } |awk -F"[ |,]" '{printf "%+11s %+10s %+10s\n",$4,$(NF-1),$NF}';echo;done
---==== hostA ====---
                 files       size
 16/09/2016          5      42.64
 17/09/2016          7      22.54

---==== hostB ====---
                 files       size
 16/09/2016          3      65.24
 17/09/2016          7      36.34

#

what to check in the awk in the loop to achieve this?:

Code:

---==== hostA ====---
       date      files       size
 16/09/2016          5      42.64
 17/09/2016          7      22.54

---==== hostB ====---
       date      files       size
 16/09/2016          3      65.24
 17/09/2016          7      36.34

w5000 · Sep 19, 2016

Update: I've figured it out

Code:

# for a in hostA hostB;do echo "---==== $a ====---";printf "%+11s %+10s %+10s\n" date files size;grep $a: inputtest|tr -s ' '|awk -F"[ |,]" '{printf "%+11s %+10s %+10s\n",$4,$(NF-1),$NF}';echo;done
---==== hostA ====---
       date      files       size
 16/09/2016          5      42.64
 17/09/2016          7      22.54

---==== hostB ====---
       date      files       size
 16/09/2016          3      65.24
 17/09/2016          7      36.34

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print first line unconditionally

w5000

Technical User

w5000

Technical User

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