Some in_array logic help please?

Question

Some in_array logic help please?

BobMCT (IS/IT--Management)

(OP)

5 Feb 16 02:29

I've been playing with this for way too long. So I thought I would ask here.

I'm trying to check if a array element value can be found as a data element in a reference array. I'm using this:
if (!in_array($arg, $arrayname, true)) {
this would occur if the $arg value is NOT found in the array
}

What I'm experiencing is even if the searched arrayname contains a substring of the $argument is returning true.
Example:

If I search for abc and the array element contains abcdef it would return found.

What do I need to do to assure the element I'm testing for is the exact same match as the argument value?
example:

If the argument was abc then the array element value must be exactly abc

Any hint, suggestions greatly appreciated.

Thanks

feherke (Programmer) · Answer 1 · 2016-02-05 11:19:20

Hi

Are you sure ? in_array() works out of the box exactly as you described :

CODE --> -a

Interactive mode enabled

php > var_dump(in_array('abc', ['abcdef']));
bool(false)

php > var_dump(in_array('abcdefghi', ['abcdef']));
bool(false)

php > var_dump(in_array('abcDEF', ['abcdef']));
bool(false)

php > var_dump(in_array('abcdef', ['abcdef']));
bool(true)

Could you post some exact input data samples for which it fails ?

Feherke.
feherke.ga

BobMCT (IS/IT--Management) · Answer 2 · 2016-02-05 15:10:58

Well it turns out that the test was operating properly all along. I added the "true" option and now it does not come back true with a "contained within" match. Also, I was improperly removing my argument which gave the impression of a true when it was not. This instruction was not one that I often used. Takes time to understand how it works.

Thanks for the thoughts.

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Some in_array logic help please?