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Some in_array logic help please?

Some in_array logic help please?

Some in_array logic help please?

I've been playing with this for way too long. So I thought I would ask here.

I'm trying to check if a array element value can be found as a data element in a reference array. I'm using this:
if (!in_array($arg, $arrayname, true)) {
this would occur if the $arg value is NOT found in the array

What I'm experiencing is even if the searched arrayname contains a substring of the $argument is returning true.

If I search for abc and the array element contains abcdef it would return found.

What do I need to do to assure the element I'm testing for is the exact same match as the argument value?

If the argument was abc then the array element value must be exactly abc

Any hint, suggestions greatly appreciated.


RE: Some in_array logic help please?


Are you sure ? in_array() works out of the box exactly as you described :

CODE --> -a

Interactive mode enabled

php > var_dump(in_array('abc', ['abcdef']));

php > var_dump(in_array('abcdefghi', ['abcdef']));

php > var_dump(in_array('abcDEF', ['abcdef']));

php > var_dump(in_array('abcdef', ['abcdef']));

Could you post some exact input data samples for which it fails ?


RE: Some in_array logic help please?

Well it turns out that the test was operating properly all along. I added the "true" option and now it does not come back true with a "contained within" match. Also, I was improperly removing my argument which gave the impression of a true when it was not. This instruction was not one that I often used. Takes time to understand how it works.

Thanks for the thoughts.

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