awk: print lines only when two lines with $NF == "string" found.
awk: print lines only when two lines with $NF == "string" found.
(OP)
hello,
print no line if only one or more than two has been found.
$ echo "1 2 3 stringA\n3 4 5 stringA"|awk '$NF == "stringA"'
1 2 3 stringA
3 4 5 stringA
current workaround:
TEST_INPUT="1 2 3 stringA\n3 4 5 stringB"
if [ `echo ${TEST_INPUT}|awk '$NF == "stringA"'|wc -l` -eq 2 ]
then
echo ${TEST_INPUT}|awk '$NF == "stringA"'
fi
can it be done with the only 'awk' command in:
echo "1 2 3 stringA\n3 4 5 stringB"|awk '$NF == "stringA"'
Talk To Other Members
RE: awk: print lines only when two lines with $NF == "string" found.
This is a typical case for double passing : first just count, when just output :
CODE --> command-line
In case your input will come from the standard input, will need the shell's process substitution feature :
CODE --> command-line
In case the input is huge, is preferable to use optimized code, even if it is abit longer :
CODE --> command-line
Feherke.
http://feherke.github.com/