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looking for lines...

looking for lines...

looking for lines...



input file (cron log file with lines) - mixed lines like:
root : CMD ( /home/den/proc400.ksh >/dev/null ) : PID ( 18940110 ) : Tue Nov 6 21:30:00 2012
root : CMD ( /home/den/clean.ksh full >/dev/null ) : PID ( 53412070 ) : Tue Nov 6 23:30:00 2012
Cron Job with pid: 18940110 Failed
Cron Job with pid: 18943456 Successful
Cron Job with pid: 19535560 Successful
Cron Job with pid: 53412070 Failed

and want to find all tasks which exited with error (Failed status).

What i wanted to do is:

for i in `grep "^Cron Job with pid" log|awk '{print $5}'|sort -u`
awk -vx=$a '$(NF-7) == x || $(NF-1) == x {print}' log|sed 'N;s/\n/,/'|grep Failed$

and then join every two lines and grep for Failed.

The problem is that
$(NF-7) == x || $(NF-1) == x
is doesn't do what I expect. I want it to find all lines having the PID number ($a) on position $(NF-1) or $(NF-7). is it possible knowing that some lines have less fields then 7?

RE: looking for lines...


Possible to misunderstood the requirement, as you posted no sample of expected output. This is based on the "join every two lines and grep for Failed" part :

CODE --> command-line

awk 'NF>10&&$(NF-9)=="PID"{p[$(NF-7)]=$0;next}$NF=="Failed"{print p[$(NF-1)],$0}' /input/file 
Tested with gawk and mawk.


RE: looking for lines...

you simply got it right winky smile

thank you!!!

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