More than one record in the same interval

Question

More than one record in the same interval

AnaIsabelFlor77 (Programmer)

(OP)

27 Oct 12 13:13

Hello,

I have a table that defines wich person is using a DB user at a time:

DB_USER ID_NAME LOGIN LOGOFF
USER1 Ana 27-10-2012 18:10:05 27-10-2012 18:18:05
USER1 John 27-10-2012 18:18:06 27-10-2012 18:28:05
USER1 Greg 27-10-2012 18:20:09 27-10-2012 18:25:05

How can I find out if more than one person was using the same DB user at that interval of time? I know that in this example it should return the following:

DB_USER ID_NAME Date
USER1 John 27-10-2012
USER1 Greg 27-10-2012

Can you help me?
Thanks

taupirho (Programmer) · Answer 1 · 2012-10-29 10:44:45

If you have workspace manager available to you check out the WM_PERIOD and WM_OVERAPS - and a few other WM_*
funtions too - which will help you solve this. Alternatively there is an undocumented Oracle SQL function called overlaps which again may be of use, although I wouldn't base any production tasks on it.

In order to understand recursion, you must first understand recursion.

SantaMufasa (TechnicalUser) · Answer 2 · 2012-10-29 16:38:36

Ana,

Given your data:

CODE

select A.DB_USER a_db_user
      ,A.ID_NAME a_id_name
      ,to_char(A.LOGIN,'dd-MON-yyyy hh24:mi:ss') a_login
      ,to_char(A.LOGOFF,'dd-MON-yyyy hh24:mi:ss') a_logoff
  from logins a
/

A_DB_USER A_ID_NAME A_LOGIN              A_LOGOFF
--------- --------- -------------------- --------------------
USER1     Ana       27-OCT-2012 18:10:05 27-OCT-2012 18:18:05
USER1     John      27-OCT-2012 18:18:06 27-OCT-2012 18:28:05
USER1     Greg      27-OCT-2012 18:20:09 27-OCT-2012 18:25:05

3 rows selected.

...there are several ways you can solve your need. Here is one way:

CODE

SELECT A.DB_USER a_db_user
      ,A.ID_NAME a_id_name
      ,to_char(A.LOGIN,'dd-MON-yyyy hh24:mi:ss') a_login
      ,to_char(A.LOGOFF,'dd-MON-yyyy hh24:mi:ss') a_logoff
      ,b.DB_USER b_db_user
      ,b.ID_NAME b_id_name
      ,to_char(b.LOGIN,'dd-MON-yyyy hh24:mi:ss')  b_login
      ,to_char(b.LOGOFF,'dd-MON-yyyy hh24:mi:ss') b_logoff
  from (SELECT DB_USER, ID_NAME, LOGIN, LOGOFF
          FROM LOGINS) A
      ,(SELECT DB_USER, ID_NAME, LOGIN, LOGOFF
          FROM LOGINS) b
 WHERE a.db_user = b.db_user
   and a.id_name <> b.id_name
   and (a.login between b.login and b.logoff
        or
        a.logoff between b.login and b.logoff)
/

A_DB_USER A_ID_NAME A_LOGIN              A_LOGOFF             B_DB_USER B_ID_NAME B_LOGIN              B_LOGOFF
--------- --------- -------------------- -------------------- --------- --------- -------------------- --------------------
USER1     Greg      27-OCT-2012 18:20:09 27-OCT-2012 18:25:05 USER1     John      27-OCT-2012 18:18:06 27-OCT-2012 18:28:05

1 row selected.

Let us know if this is satisfactory and if you have additional questions.

santa Mufasa
(aka Dave of Sandy, Utah, USA)
“People may forget what you say, but they will never forget how you made them feel."

AnaIsabelFlor77 (Programmer) · Answer 3 · 2012-10-30 06:00:14

RE: More than one record in the same interval

AnaIsabelFlor77 (Programmer)

(OP)

30 Oct 12 06:00

Hello,

It worked. Thanks for all your help.

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More than one record in the same interval