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awk within variable

awk within variable

awk within variable

Hello everyone,

could you help me out with a little problem (I'm quite new to perl):

I got the following output:
(Note: I'm using AIX / Linux)


ls -all /datastore/backup

-rw-r--r-- 1 root root 6431369457 Jul 10 07:57 /datastore/backup 

What I'd like to do is store only the "Jul 10" in a variable ...

Cutting it out is easy:


ls -all /datastore/backup | awk '{print $6 " " $7}' 

But how do I get this stored within a variable ?

Using the following stores the whole string within the variable and NOT only the "Jul 10":


$dat2=`ls -all /datastore/backup | awk '{print $6 " " $7}'`;
print $dat2, "\n";

-rw-r--r-- 1 root root 6431369457 Jul 10 07:57 /datastore/backup 

Thomas Schmitt

RE: awk within variable


Just to correct your code, escape the dollar signs ( $ ) :

CODE --> (fragment)

$dat2=`ls -all /datastore/backup | awk '{print \$6 " " \$7}'`; 

But would be preferable to forget such shell scripting practices when coding in Perl.

In case /datastore/backup is a single file to check, this will print its modification time in local date time format :

CODE --> Perl

@stat=stat '/datastore/backup';
print scalar localtime $stat[9]; 


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